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函数f(x)的定义域是R,f(0)=2,对任意x∈R,f(x)+f′(x)>1,则不等式e x·f(x)>e x+1的解集为(  )

发布时间:2021-07-16

A.{x|x>0}

B.{x|x<0}

C.{x|x<-1或x>1}

D.{x|x<-1或0<x<1}

试卷相关题目

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