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已知R上的不间断函数g(x)满足:①当x>0时,g′(x)>0恒成立;②对任意的x∈R都有g(x)=g(-x)。 又函数f(x)满足:对任意的x∈R,都有f(http://picflow.koolearn.com/upload/papers/g02/20120503/20120503102327999883.gif+x)=-f(x)成立,当x∈[0,http://picflow.koolearn.com/upload/papers/g02/20120503/20120503102328046883.gif]时,f(x)=x3-3x。若关于x的不等式g[f(x)]≤g(a2-a+2)对x∈[-3,3]恒成立,则a的取值范围

发布时间:2021-07-15

A.a≤0或a≥1

B.0≤a≤1

C.-1≤a≤1

D.a∈R

试卷相关题目

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